Schedule and Homework

 

Week

Date

Topics

Homework

Due date

1

May 31st

Ch 1,8,2

Ch1,12; Ch2,1,10; Ch8,1

June 6th

June 1st

Logic, Ch 3,4

Ch3,1; Ch4,1; Problem1

June 2nd

Ch 5

Problem2,3,4

 

2

June 6th

Ch 5(continued)

Ch5,1,8; Problem 5,6

June 13th

June 7th

Ch 6

Ch6,1,3

June 8th

Ch 7,8,8 Appendix, Exercises

Ch7,11

June 9th

Ch 9

Ch9,1,7,10

 

3

June 13th

Ch 10

Ch10,1,2,4,5

June 21th

June 14th

Ch 10(continued)

Ch10,8,11

June 15th

Ch 11

Ch11,1,2,3,25

June 16th

Ch 11(continued), Review

No Homework

 

4

June 20th

Midterm

No Homework

June 27th

June 21st

Exercises

No Homework

June 22nd

Ch 13

Ch13,9; Problem 7,8

June 23rd

Ch 14

Ch14,1,4,5,11

 

5

June 27th

Ch 15,18,19

Ch15,1,2; Ch18,1; Ch19,1

Not Collected

June 28th

Quiz, Course Review

Ch19,2,3

June 29th

Quiz, Course Review(continued)

 

June 30th

Final Exam

 

 

 

Additional assignments:

 

Problem1:

What is the contrapositive of the following statement?

1.      The “well-ordering principle”.

2.      For any real numbers a, b, c, if ab=ac, then either a=0 or b=c.

3.      For any real numbers a, b, if a, b>0, then ab>0.

Explaining the following statements by method of negation.

1.      A is not bounded below.

2.      x is not an upper bound of A.

3.      x is not a least upper bound of A.

 

Problem2:

Write the formal definition of “the function f approaches the limit L near a” for ten times.

 

Problem3:

Prove that the function f(x)=sqrt(x,3) (cubic root of x) approaches 0 near 0.

 

Problem4:

Prove that the function f(x)=|x| approaches 1 near 1.

 

Problem5:

Prove that if lim_{x->a}g(x)=m, lim_{x->m}f(x)=L=f(m), then lim_{x->a}f(g(x))=L.

 

Problem6:

Prove the following by the formal definition of “the function f approaches the limit L near a”:

(1)            lim_{x->a}x^n=a^n, where n is an integer;

(2)            lim_{x->a}sqrt(x)=sqrt(a), where a>0. (sqrt(a) means the positive square root of a.)

 

Problem7:

Prove Theorem7 in Chapter13.

 

Problem8:

Let f(x) be a function defined on [0,2], whose value is 1 at 1 and 0 elsewhere.

Prove that f is integrable on [0,2], and its integration over [0,2] is 0.