Schedule and Homework
|
Week |
Date |
Topics |
Homework |
Due date |
|
1 |
May 31st |
Ch 1,8,2 |
Ch1,12; Ch2,1,10; Ch8,1 |
June 6th |
|
June 1st |
Logic, Ch 3,4 |
Ch3,1; Ch4,1; Problem1 |
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June 2nd |
Ch 5 |
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2 |
June 6th |
Ch 5(continued) |
Ch5,1,8; Problem 5,6 |
June 13th |
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June 7th |
Ch 6 |
Ch6,1,3 |
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June 8th |
Ch 7,8,8 Appendix, Exercises |
Ch7,11 |
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June 9th |
Ch 9 |
Ch9,1,7,10 |
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3 |
June 13th |
Ch 10 |
Ch10,1,2,4,5 |
June 21th |
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June 14th |
Ch 10(continued) |
Ch10,8,11 |
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June 15th |
Ch 11 |
Ch11,1,2,3,25 |
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June 16th |
Ch 11(continued), Review |
No Homework |
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4 |
June 20th |
Midterm |
No Homework |
June 27th |
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June 21st |
Exercises |
No Homework |
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June 22nd |
Ch 13 |
Ch13,9; Problem 7,8 |
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June 23rd |
Ch 14 |
Ch14,1,4,5,11 |
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5 |
June 27th |
Ch 15,18,19 |
Ch15,1,2; Ch18,1; Ch19,1 |
Not Collected |
|
June 28th |
Quiz, Course Review |
Ch19,2,3 |
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June 29th |
Quiz, Course Review(continued) |
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June 30th |
Final Exam |
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Additional
assignments:
What is the contrapositive
of the following statement?
1.
The “well-ordering
principle”.
2.
For any real numbers
a, b, c, if ab=ac, then either a=0 or b=c.
3.
For any real numbers
a, b, if a, b>0, then ab>0.
Explaining the
following statements by method of negation.
1.
A is not bounded
below.
2.
x is not an upper bound of A.
3.
x is not a least upper bound of A.
Write the formal definition of “the function
f approaches the limit L near a” for ten times.
Problem3:
Prove that the function f(x)=sqrt(x,3) (cubic root of x)
approaches 0 near 0.
Problem4:
Prove that the function f(x)=|x| approaches 1 near 1.
Prove that if lim_{x->a}g(x)=m, lim_{x->m}f(x)=L=f(m),
then lim_{x->a}f(g(x))=L.
Problem6:
Prove the following by the formal definition
of “the function f approaches the limit L near a”:
(1)
lim_{x->a}x^n=a^n, where n is an integer;
(2)
lim_{x->a}sqrt(x)=sqrt(a), where
a>0. (sqrt(a) means the positive square root of a.)
Prove Theorem7 in Chapter13.
Problem8:
Let f(x) be a function defined on [0,2], whose value is 1 at 1 and 0 elsewhere.
Prove that f is integrable on [0,2], and its integration over [0,2] is 0.